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The original LHS can actually be simplified to r in about 3 steps as Mark was hinting at earlier The first part of your statement, "~p" says that p is false That means that "p^r" is false so that statement reduces to " (~q^r)v (q^r)" If q is false, "q^r" is false so we must have "~q^r" and so r& r p p h ufld o lq t x lulh v r u ulj k wv d q g s h up lvvlr q v uh t x h vwv vk r x og e h g luh fwh g wr wk h lq g lylg x d o s x e olvk h u d v fr s \ulj k w k r og h u % lr2 q h vh h v vx vwd lqd e oh vfk r oduo\ s x e olvk lqj d v d q lqk h uh q wo\ fr oode r ud wlyh h q wh us ulvh fr q q h fwlqj d x wk r uv q r q s ur ilw s x e olvk h11 PROPOSITIONS 7 p q ¬p p∧q p∨q p⊕q p → q p ↔ q T T F T T F T T T F F F T T F F F T T F T T T F F F T F F F T T Note that ∨ represents a nonexclusive or, ie, p∨ q is true when any of p, q is true and also when both are true On the other hand ⊕ represents an exclusive or, ie, p⊕ q is true only when exactly one of p and q is true 112
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